[3x-4(3x+y)]=

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Solution for [3x-4(3x+y)]= equation:


Simplifying
[3x + -4(3x + y)] = 0
[3x + (3x * -4 + y * -4)] = 0
[3x + (-12x + -4y)] = 0

Combine like terms: 3x + -12x = -9x
[-9x + -4y] = 0

Remove brackets around [-9x + -4y]
-9x + -4y = 0

Solving
-9x + -4y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y' to each side of the equation.
-9x + -4y + 4y = 0 + 4y

Combine like terms: -4y + 4y = 0
-9x + 0 = 0 + 4y
-9x = 0 + 4y
Remove the zero:
-9x = 4y

Divide each side by '-9'.
x = -0.4444444444y

Simplifying
x = -0.4444444444y

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